What’s the Letter or WHAT’l 这个数字代表哪个字母？

We have devised a new word game called ” What’l “. We were inspired by Simon Shuker’s Code-Cracker. But instead of a 13 x 13 grid, we go for a 10 x 10 grid and we incorporated Names for each cell of the grid by calling the rows 1 through to 10 and the columns ‘ A or a ‘ through to ‘ L or l ‘. Here are two examples of the basic 10 x 10 grid of a What’l challenge, with the blank cells coloured in:

我们设计了一个名为“What'l”的新文字游戏。我们受到 Simon Shuker 的 Code-Cracker 的启发。但是我们不是使用 13 x 13 的网格，而是使用 10 x 10 的网格，并且我们通过调用第 1 到 10 行以及从“A 或 a”到“L 或 l”的列来为网格的每个单元格合并名称.以下是 What'l 挑战的基本 10 x 10 网格的两个示例，空白单元格已着色：

Unlike Simon Shuker’s, WHAT’L is directed to the younger players and so more clues are provided. Also, the words are mainly shorter and this helps the players in vocabulary building. Words are handpicked from reading lists found on the internet. One example of this is the website https://wrightstd5.weebly.com/uploads/5/2/1/7/5217692/240vocabularywords.pdf with a sample page shown below:

与 Simon Shuker 不同的是，WHAT'L 是针对年轻玩家的，因此提供了更多线索。此外，单词主要是较短的，这有助于玩家建立词汇量。单词是从互联网上的阅读列表中挑选出来的。这方面的一个例子是网站 https://wrightstd5.weebly.com/uploads/5/2/1/7/5217692/240vocabularywords.pdf，其示例页面如下所示：

Let us now discuss one sample puzzle shown below:

现在让我们讨论一个示例拼图，如下所示：

For each number, find the letter that the number represents, given the seven clues for this puzzle as follow: : 1 = E; 3 = A; 8 = L; 18 = N; 22=W; 23 = Z; and 24 = D.

对于每个数字，找到该数字所代表的字母，给出这个谜题的七个线索如下： : 1 = E; 3 = A； 8 = L; 18 = N; 22=W; 23 = Z;和 24 = D。

Fill into the grid all those seven numbers given. For example, cell A1 = 1 = E = cell F1 = cell J1; cell C1 = 3 = A = cell H1 = cell A2 = cell i2; and so on, to give us the following outcome:

将给定的所有七个数字填入网格。例如，单元格 A1 = 1 = E = 单元格 F1 = 单元格 J1；单元格 C1 = 3 = A = 单元格 H1 = 单元格 A2 = 单元格 i2；等等，给我们以下结果：

With this done, we turn our attention to cells J8, J9, J10. ( 10; D; E). It is easy to for us to conclude that 10 = O. Vocabulary here: ODE means “a lyric poem, typically one in the form of an address to a particular subject, written in varied or irregular metre beats.”

完成此操作后，我们将注意力转向单元格 J8、J9、J10。 (10；D；E)。我们很容易得出结论 10 = O。这里的词汇：ODE 的意思是“一首抒情诗，通常以针对特定主题的地址的形式写成，以不同或不规则的节拍写成。”

The seven lettered word at cell C1 down comes to our attention: A L L E 14; 6; O. The word here is Allegro, meaning “at a brisk speed, as in a piece of classical music. So, 14 = G; and 6 = R. We now fill all number 14s with G and all 6s with R. The grid now looks as follows:

我们注意到单元格 C1 下方的七个字母单词：A L L E 14； 6; O。这里的词是 Allegro，意思是“以轻快的速度，就像在一段古典音乐中一样。所以，14 = G；和 6 = R。我们现在用 G 填充所有数字 14，用 R 填充所有 6。网格现在如下所示:

With ALLEGRO done we find that the ten-letter word starting at cell A1 across is easy. Only the word E X A S P E R A T E. Exasperate means “irritate and frustrate (someone) intensely”. So, 2 = X; 4 = S; 5 = P; and 7 = T.

完成 ALLEGRO 后，我们发现从单元格 A1 开始的十个字母单词很容易。只有 E X A S P E R A T E 这个词。 Exasperate 的意思是“强烈地激怒和挫败（某人）”。所以，2 = X； 4 = S; 5 = P; 和 7 = T。

The word at cell G1 down is ROES, which is a bonus. The word ROE means “the mass of eggs contained in the ovaries of a female fish or shellfish, especially when ripe and used as food.”

单元格 G1 下方的单词是 ROES，这是一个奖励。 ROE这个词的意思是“雌性鱼或贝类卵巢中所含的大量卵子，尤其是在成熟并用作食物时。”

If we now look at the four-letter word at cell I 1 down T A X 13; it is easy to guess that 13 = I for TAXI with another word found in cell I 4 across - I T. Next, for the word at cell A1 down, E A 11; E S, the word is EAVES which means “the part of a roof that meets or overhangs the walls of a building”. So, 11 = V. The word at cell A3 across, V 12; L T 12; R E has to be VULTURE (12 = U) and VULTURE means “a large bird of prey feeding chiefly on recent dead meat of a sick or injured animal or person”.

如果我们现在看一下 T A X 13 下单元格 I 1 的四个字母的单词；很容易猜到 TAXI 的 13 = I 以及在单元格 I 4 中找到的另一个单词 - I T。接下来，对于单元格 A1 向下的单词，E A 11； E S，这个词是 EAVES，意思是“屋顶与建筑物墙壁相遇或悬垂的部分”。因此，11 = V。单元格 A3 中的单词 V 12；L T 12; R E 必须是 VULTURE (12 = U)，而 VULTURE 的意思是“一种大型猛禽，主要以最近生病或受伤的动物或人的死肉为食”。

15 is easy to guess and cell A5 across has 15 as the only missing letter. The word is therefore SIGMA with 15 = M. This letter M can easily fit the three letter word at cell C5 down - AIM. We are now left with the numbers 9; 16; 17; 19; 20; 21; 25; and 26 for the letters B; C; H; J; K; P; and Y. Digit 17 = H for the word THE at cell J4 down can be confirmed. With this, the word in D7 becomes HAZY, that is 26 = Y. Hazy means “covered by a haze, or for describing a person, confused.”

15 很容易猜到，A5 单元格中唯一的缺失字母是 15。因此这个词是 SIGMA 和 15 = M。这个字母 M 可以很容易地适合单元格 C5 向下的三个字母词 - AIM。我们现在只剩下数字 9； 16; 17; 19; 20; 21; 25;和 26 表示字母 B； C; H; Ĵ; ķ;磷；和 Y. 数字 17 = H 可以确认单元格 J4 下的单词 THE。这样，D7 中的单词就变成了 HAZY，即 26 = Y。Hazy 的意思是“被阴霾笼罩，或用于描述一个人，迷茫”。

Digit 19 can only be J for INJURE in cell E6 across. That leaves 21 to be C for CAW as 21 cannot be L (as 8 = L), and cannot be J for JAW, (as 19 = J). CAW is the cry of the black bird, crow. That leaves us with B; K; P; and Q.

数字 19 只能是 J 表示单元格 E6 中的 INJURE。这使得 CAW 的 21 成为 C，因为 21 不能是 L（因为 8 = L），也不能是 JAW（因为 19 = J）。 CAW 是黑鸟鸦的叫声。剩下的就是B; K; P; 和 Q。

Using the dictionary we find 20 = B as ABOHM is one particular Ohm - the measurement of electrical resistance. Then cell B 7 down is BEEP with 25 = P. The last two words are QUIRAS (16 = Q) and PKU (9 = K). ‘Quiras’ is a noun and is one type of tropical tree found in America with hard and heavy red wood. Pku is a word that means “a rare inherited disorder that causes an amino acid called phenylalanine to build up in the body”.

使用字典我们发现 20 = B 因为 ABOHM 是一个特殊的欧姆 - 电阻的测量值。然后单元格 B 7 向下是 25 = P 的 BEEP。最后两个单词是 QUIRAS (16 = Q) 和 PKU (9 = K)。 'Quiras' 是一个名词，是在美国发现的一种热带树，有坚硬而沉重的红木。 Pku 是一个词，意思是“一种罕见的遗传性疾病，会导致一种叫做苯丙氨酸的氨基酸在体内积聚”。